This post will show you how to solve order operations questions.This mathematics involved only four sets of operators which are:Addition;Subtraction;Multiplication and Division.With these operators,an order operations can be solve.This mathematics have different rule that must be follow before its can be done.
Order Operation Rules
1. You must do the operation inside the bracket first.
2. You must multiply and divide next , if only ''of'' occurs within the fractions,then replace ''of'' with x (multiplication sign.
3. You must do addition first,then subtraction last.
We can see that the rules are simply called BODMAS. Which means:
Bracket Of
Division;
Multiplication;
Addition'
Subtraction
With the above rules,order of operation can be manipulated.In this lesson, i will solve some questions on this topic.
Example 1
Simplify this
1 2 1 2
a)4 ------------ x 3 --------- x-------- ÷ 3 -----------
2 3 9 3
3 1 1
= ----------- x ------------ x --------- x ------------
2 3 9 11
1 3
1
= -------------
2 x 3
1
1
= ----------
2
That was a great mathematical working by multiplying those fractions before division.Another thing you need to notice is how those numbers go to themselves. Also, any time you have division sign in between two fractions and the second one is mixed number,when changing to improper fractions observe the reciprocal of that second fraction i mean:
1 2
----------- ÷ 3 --------------
9 3
1 11
= ------------- x -----------
9 3
11
reciprocal of -------------
3
They respect each other by 3 coming down for 11 to be on top.
3 1 1
b) ------------ ÷ ------------- x 1 -----------
8 12 12
1
3 12 13
= ------------ x ------------ x ------------
8 1 12
1
3 x 13
= --------------
8
7
= 4---------
8
In the above operation, you will notice that i also observed the reciprocal of the second fraction.
Example 2
Solve this operation.
1 1 4 15
i) --------- x -------- + --------- x ---------
3 4 5 16
1 3
1 1 4 15
= --------- x -------- + --------- x ---------
3 4 5 16
1 4
L.C.M of 12 and 4 = 12
1 9
= ------------ + -----------
12 12
1 + 9
= --------------------
12
5
= ------------
6
5
= ----------
6
That was so good and interesting one, 1 first multiply the first two fractions before dividing the second fractions.
ii) Solve this operation.
1 1 3 1
1 ---------- ÷ --------- - ---------- x ---------
6 3 4 2
7 3 3 1
= ---------- x --------- - ---------- x ---------
6 1 4 2
1
7 3 3
= ---------- x ---------- - ----------
2
7 3
= ---------- - ---------
2 8
L.C.M of 2 and 8 = 8
28 - 3
= -----------------------
8
25
= -------------
8
1
= 3 ----------
8
The second examples can be done by multiplying before division.
Example 3
Now solve the this:
2 2 1 3
a)--------- x (--------- - ----------) ÷ ----------
3 4 8 4
2 3 1 3
= --------- x (--------- - ----------) ÷ ----------
3 4 8 4
L.C.M of 4 and 8 = 8
2 6 - 1 3
= --------- x (--------- ) ÷ ----------
3 8 4
1
= ----------- x ---------- x ---------
3 8 3
5
= ------------
9
The third examples shows that, fraction in the bracket must be manipulate before multiplication and do not forget to replace "of" with x.
4 4 2 2
b) ---------- of ( --------- + -------- ) ÷ 2---------
5 9 3 3
4 4 2 2
= ---------- of ( --------- + -------- ) ÷ 2---------
5 9 3 3
4 4 + 6 2
= -------- x ( --------------) x 2 -----------
5 9 3
1 2
= ----------- x ------------ x ----------
1 3 2
1 x 2
=--------------
3 x 2
1
= ------------
3
1
= ----------
3
That was a great working, please if there is anything you don't understand kindly put your questions in the comment box.
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